Details for problem "Direct proportionality - complete table"
Quickname: 6246
Suitable for K-12 grades: Grade 6 Grade 7
Elementary School, Primary School, Junior High School, Middle School, High School.
Summary
Apply the rule of three for a direct proportionality relationship and fill in missing values in a table.
Example
Description
A rule of three problem for a direct proportionality relationship has to be solved. It is presented in the form of a table. To solve the problem, complete the table by filling in the missing values.
The table is provided with values that will be sufficient to solve the problem. The difficulty of the problem is depending on the values that are provided and the values that have to be calculated and derived from others.
The values of the tables are as follows:
| argument x1>1
|
|
value y1
|
| divisor on left
|
|
divisor on right
|
| argument x2=1
|
|
value y2
|
| factor on left
|
=
|
factor on right
|
| argument x3≠x1
|
|
value y3
|
The level of difficulty can be chosen from five levels. The level of difficulty determined what values will be provided with the table:
- Level 1
- Argument x1, value y1, divisor on left, argument x2, argument x3 are given. The solution is straightforward.
- Level 2
- Argument x1 and value y1 plus others are given as necessary so that values have to be derived in a way that the table can be filled from top to bottom down the table rows.
- Level 3
- Argument x1, value y1 are provided together with x3 on the left or value y3 on the right, so value will have to be derived in a bottom to top way too.
- Level 4
- Only one of argument x1 or value y1 are given, plus others as necessary to solve the problem.
- Level 5
- Neither argument x1 nor value y1 are given, the derivation of values from others will have to be performed in a bottom up fashion.
The number of problems is selectable. The first problem may be presented as a sample problem, showing the complete table with all values. A number range can be chosen for the numbers appearing in the table.
Topics: Arithmetic Elementary arithmetic Functions Units Written form
Tags: Division Multiplication
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Customization options for this problem
Number of problems
1, 2, 3, 4, 5, 6, 7, 8
Number range
100, 200, 500, 1000, 10000, 100000
Level of difficulty
1, 2, 3, 4, 5
Similar problems
Similar problem for inversely proportional relationships
Apply the rule of three for an inverse proportionality relationship and fill in missing values in a table.
In the form of a word problem
Word problems that can be solved by applying the rule of three.
Easier text problem where the proportionality constant is given (rule of two)
Easy word problems that can be solved by applying the rule of three. No initial division necessary, first factor is one.
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